Question

The function below describes the curve that forms a graph of the cross-section for a parabolic dish. 12x^2−11x+2What is the sum of the zeros for the function?5 over 1213 over 127 over 1211/12

Answer 1

`12x^2-11x+2`

start making the function equal to 0,

`12x^2-11x+2=0`

use the quadratic formula in order to find the zeros of the function,

`\begin{gathered} x=(-b\pm√(b^2-4ac))/(2a) \\ a=12;b=-11;c=2 \\ x=(-(-11)\pm√((-11)^2-4(12)(2)))/(2(12)) \\ x=(11\pm√(121-96))/(24) \\ x=(11\pm√(25))/(24) \\ x_1=(11+5)/(24);x_2=(11-5)/(24) \\ x_1=(2)/(3);x_2=(1)/(4) \end{gathered}`

finally, add both of the solutions

`(1)/(4)+(2)/(3)=(3+4\ast2)/(12)=(11)/(12)`

Answer:

The sum of the zeros for the function is 11/12