Question

In 2010, the population of a city was 109,000. From 2010 to 2015, the population grew by 6.7%. From 2015 to 2020, it fell by 6%. To the nearest 100 people, what was the population in 2020?

Answer 1

`\begin{gathered} \text{population in 2010 = 109,000} \\ \text{from year 2010 to 2015: growth percentage is(6.7\%) : }(6.7)/(100)\text{ }*109,000 \\ \text{ = 7,303} \\ \text{ New population value in 2015 is: ( 109,000 + 7,303 ) = 116,303} \\ \text{from year 2015 to 2020 : percentage Decrease is (6\%) : }(6)/(100)*116303 \\ \text{ = 0.06 }*\text{ }116303 \\ \text{ = 6,978.18 }\approx6978\text{ } \\ New\text{ population value in 2020 is : }116,303\text{ - }6978\text{ } \\ \text{ = 109,325} \\ \text{109,325 t}o\text{ the nearest hundred is: 109,300} \end{gathered}`