Question

A certain shade of blue has a frequency of 7.00 × 1014 Hz. What is the energy of exactly one photon of this light?

Answer 1

Energy = Planck's constant * Frequency

E = (6.62607004 × 10⁻³⁴) * 7 * 10¹⁴

E = 46.38 * 10⁻²⁰

E = 4.638 * 10⁻¹⁹ J

Hope this helps!

Answer 2

Answer : The energy of exactly one photon of this light is
`4.64* 10^(-19)J`

Explanation : Given,

Frequency of blue light =
`7.00* 10^(14)Hz=7.00* 10^(14)s^(-1)`

Formula used :

`E=h* \\u`

where,

`\\u` = frequency of light

h = Planck's constant =
`6.626* 10^(-34)Js`

Now put all the given values in the above formula, we get:

`E=(6.626* 10^(-34)Js)* (7.00* 10^(14)s^(-1))`

`E=4.64* 10^(-19)J`

Therefore, the energy of exactly one photon of this light is
`4.64* 10^(-19)J`