What is the magnitude of the orbital velocity of the earth in m/s?

asked Mar 25, 2018 12.7k views

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Circumference C=2πr
C=2π(1.5x10^8)=9.42x10^8

In 365 Days there are 8760hr

V=distance/time

V=(9.42x10^8)/8760=107534.2km/hr

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