Question

Three nails have a mass of 3.05 g. how many moles of iron do the contain?

Answer 1

Data:
3 nails of iron = 3.05 g (by nail)

The atomic mass of iron is 55.845 amu, so the molar mass is: M = 55.845 → M ≈ 56 g / mol

With a simple 3 rule:

56 g → 1 mol
3.05 g → y mol

Portanto:

`(56)/(3.05) = (1)/(y)`


`56*y = 1*3.05`

`56y = 3.05`

`y = (3.05)/(56)`

`\boxed{y = 0.05446... mol}}`

Soon:
3 nails → 3*0.05446... = 0.1638...mols

Answer 2

Answer: 0.05 moles

Explanation: According to Avogadro's law, 1 mole of every substance contains Avogadro's number of particles and weighs equal to the molar mass of the substance.

`Moles=\frac{\text{Given mass}}{\text{Molar mass}}`

Given mass = 3.05 g

Molar mass of iron = 56 g/mol

`Moles=(3.05g)/(56g/mol)=0.05moles`