Let P represent no of parrots and S represent no of snakes.
The parrots increase by 15% so at the end of each year, the population of P represented by nP is nP = (P + 0.15P).
4 new snakes are born every year so the population of S represented by nS is nS = S +(0.17S).
PART B
At end of 1st year, no of parrots will be 20+ (0.15 x 20) = 23 parrots
At end of 2nd year. there will be 23 +(0.15 x 23) = 26 parrots
At end of 3rd year there will be 26 + (0.15 x 26) = 30 parrots
At end of 4th year, there will be 30 + (0.15 x30) = 35 parrots
At end of 5th year, there will be 35 + (0.15 x 35) = 40 parrots
At the end of 6th year, there will be 40 + 0.15 x 40) = 46 parrots
At the end of 7th year, there will be 46 + (0.15 x 46) = 53 parrots
At the end of 8th year, there will be 53 + (0.15 x 53) = 61 parrots
At the end of 9th year, there will be 61 + (0.15 x 61) = 70 parrots
At the end of 10th year, there will be 70+ (0.15 x 70) = 81 parrots
Four more snakes are born each year, so at the end of 10 years 40 snakes would have been added and the population would then be (24 + 40) = 64 snakes.
PART C
After approximately 6 years, the population of parrots nP = P' + (0.15 x P')
where P' is the number of parrots at the beginning of the year. This will give a total parrot population of 46; similarly, a total of 6 x 4 = 24 new snakes would have been added to bring the total to (24 + 24) = 48 snakes.