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The equation h(t)=−16t^2+70t+40 gives the height of a toy rocket, in feet, t seconds after it is launched from a platform.

What is the height of the platform?

User Unbekant
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2 Answers

4 votes
Here, Function: h(t)= -16t² + 70t + 40

So, put the value of t, (time at which you want to calculate the height)

h(1) = -16(1)² + 70(1) + 40
h(1) = -16 + 110
h(1) = 94

Now, h(2) = -16(2)² + 70(2) + 40
h(2) = -64 + 180
h(2) = 116

h(3) = -16(3)² + 70(3) + 40
h(3) = -144 + 250
h(3) = 106

In short, Your height depends on time, and at each time it would be different, can be expressed by the coordinates on a Graph: (1, 94) (2, 116) (3, 106)

Hope this helps!
User Zimex
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8.6k points
6 votes

Answer:

40

Explanation:

See pic attached

The equation h(t)=−16t^2+70t+40 gives the height of a toy rocket, in feet, t seconds-example-1
User Kodekan
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7.8k points