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If s(x) = 2x2 + 3x - 4, and t(x) = x + 4 then s(x) · t(x) =
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If s(x) = 2x2 + 3x - 4, and t(x) = x + 4 then s(x) · t(x) =

User Fosho
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2 Answers

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2x^3+11x^2+8x-16 ...............
User Firstresponder
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You simply multiply the two and distribute to solve. I am starting with t(x) because I think it is easier.

(x+4)*(2x^2+3x-4)
2x^3+3x^2-4x+8x^2+12x-16 (distribute)
2x^3+11x^2+8x-16 (combine like terms)
User Jenise
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