Find the discriminant of x^2+6x+13=0. What does this number tell you about how many real solutions there are to the equation? Show work/steps.

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asked Mar 21, 2018 233k views

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LeDYoM · Answer 1 · 2018-03-25T17:35:44+0000

Discriminant = sq root of b^2 - 4*a*c =
sq root of 36 - 4*1*13 =
sq root 36 -52 =
sq root 36 -52 =
sq root -16
There are no real solutions for this equation. Both roots are complex numbers.

Find the discriminant of x^2+6x+13=0. What does this number tell you about how many real solutions there are to the equation? Show work/steps.

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