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The cost of items at store A is approximately Normally distributed with a mean of $4.15 and a standard deviation of $2.68. The cost of items at store B is approximately Normally distributed with a mean of $5.35 and a standard deviation of $1.75. Assume that A (the cost of a randomly selected item from store A) and B (the cost of a randomly selected item from store B) are independent random variables. Let D = A-B. Which of the following correctly interprets the mean of D?

o $1.20. One randomly chosen item will cost $1.20 less at store A than at store B.

0 -$1.20. On average, a person can expect to spend $1.20 less at store A than at store B for many randomly chosen items.

O $1.20. One randomly chosen item will cost $1.20 more at store A than at store B.

O $1.20. On average, a person can expect to spend $1.20 more at store A than at store B for many randomly chosen items.

O $9.50. On average, a person can expect to spend a total of $9.50 at stores A and B. ​

User Dzinic
by
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1 Answer

4 votes

Answer:

Explanation:

Its b I used chegg

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User Johannes
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5.5k points
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