234k views
5 votes
I really need help for this chemistry question. Steps and how it was worked out would be helpful!

I really need help for this chemistry question. Steps and how it was worked out would-example-1
User Kishan B
by
7.9k points

1 Answer

4 votes
Data:
V (volume) = 500.0 mL = 0.5 L
T (temperature) = 15.00ºC
(converting in Kelvin) → TK = TC + 273 → TK = 15 + 273 = 288 K
P (pressure) = 736.0 mmHg
R (constant) = 62.363 (mmHg*L/mol*K)
m (mass) = 2.688 g
M (Molar Mass) = ? (g/mol)

Formula: General Gas Equation

P*V = n*R*T \to \boxed{P*V = (m)/(M) *R*T}

Solving:

P*V = (m)/(M) *R*T

736*0.5 = (2.688)/(M) *62.363*288

368 = (2.688)/(M) *17960.544
Product of extremes equals product of means:

368*M = 2.688*17960.544

368M = 48277.94227

M = (48277.94227)/(368)

M = 131.1900605\to \boxed{\boxed{M \approx 131.2\:g/mol}}

Therefore: The gas found to have such a molar mass is xenon gas



User Veli Gebrev
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.