Question

A container holds 283 ml of chlorine gas (cl2. assuming that the gas sample is at stp, what is its mass?

Answer 1

Data:
STP means
T = 0ºC or 273 K
P = 1 atm
V = 283 mL = 0.283 L
R = 0.082 atm*L/mol*K

Formula: Find "n" moles


`n = (P*V)/(R*T)`

Solving:


`n = (P*V)/(R*T)`

`n = (1*0.283)/(0.082*273)`

`n = (0.283)/(22.3)`

`\boxed{n \approx 0.01\;mol}`

Now find the mass
Knowing that the molar mass of
`Cl_(2)` = 71 g / mol


`0.01\:\diagup\!\!\!\!\!\!mol* (71\:grams)/(1\:\diagup\!\!\!\!\!\!mol) = \boxed{\boxed{0.71\:grams\: Cl_(2) }}\end{array}}\qquad\quad\checkmark`