Question

An athlete competing in the long jump leaves the ground with a speed of 9.14 m/s at an angle of 55° with the vertical. what is the length of the athlete's jump if air resistance is of no significance?

Answer 1

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Answer 2

8.01 m

Step-by-step explanation:

Initial speed of the athlete, u = 9.14 m/s

angle from the vertical = 55°

⇒angle from the horizontal, θ = 90°-55° = 35°

length of the athlete's jump can be calculated using the formula:

`R = (u^2 sin2\theta)/(g)`

Substitute the values:

`R =(9.14^2sin (2* 35^o))/(9.8)=8.01 m`