Question

A 0.20 kg mass attached to the end of a spring causes it to stretch 3.0 cm. What is the spring constant? What is the potential energy of the spring?

Answer 1

Given that the mass is m = 0.2 kg and the displacement is x = 3 cm = 0.03 m

We have to find the spring constant and potential energy.

The spring constant can be calculated by the formula

`\begin{gathered} F=\text{ kx} \\ mg\text{ = kx} \\ k\text{ = }(mg)/(x) \end{gathered}`

Here, k is the spring constant.

g = 9.8 m/s^2 is the acceleration due to gravity.

Substituting the values, the spring constant will be

`\begin{gathered} k=(0.2*9.8)/(0.03) \\ =\text{ 65.33 N/m } \end{gathered}`

The potential energy can be calculated as

`\begin{gathered} U=(1)/(2)kx^2 \\ =(1)/(2)*65.33\text{ }*(0.03)^2 \\ =\text{ 0.0293 J} \end{gathered}`