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Simplify the complex fraction .

N-6/n^2+11n+24/n+1/n+3

A-(n-6)(n+1)/(n+3)^2(n+8)

B-(n-6)(n+8)/(n+1)(n-8)

C-(n-6)(n+1)/(n+3)(n+8)

D-n-6 /(n+1)(n+8)

User Erik Mork
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2 Answers

5 votes

Answer:

d

Step-by-step explanation:hope this helps!! (: (: (:

User Sjmartin
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2 votes
N-6/n²+11n+24/n+1/n+3

First, we need to factor the following:
n² + 11n + 24 → (n + 3)(n + 8)
n² → n * n
factor of 24 are:
1 x 24
2 x 12
3 x 8 We will use these factors. 3 + 8 = 11
4 x 6

Division involving fractions results to multiplying the first fraction to the reciprocal of the second fraction.

n-6/(n+3)(n+8) * n+3 / n+1 → n+3 is in both numerator and denominator. Cancel each other out.

n-6/n+8 * 1/n+1
n-6/(n+8)(n+1) Correct answer is Choice D.
User Lizesh Shakya
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