You drop a rock off a bridge. The rock’s height, h (in feet above the water), after t seconds is modeled by h = -16t2 + 541. What is the height of the rock after 2 seconds? A. –64 feet B. 605 feet C. 509

asked Feb 13, 2018 168k views

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h = -16t^2 + 541
Put t=2 second in the equation

h=-16*4+541
h=477 feet

Bobylito answered Feb 19, 2018

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