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Triangle XYZ is rotated 270° counterclockwise about the origin.The result is AX'Y'Z', as shown below.

Triangle XYZ is rotated 270° counterclockwise about the origin.The result is AX'Y-example-1
User Ivan Kinash
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1 Answer

13 votes
13 votes

Given the coordinates of XYZ:

X(-5, -4), Y(2, -2), Z(-3, -6)

Here, triangle XYZ was rotated 270 degrees counterclockwise about the origin to get traingle X'Y'Z'.

Let's answer the following.

• Part A.

Let's determine the coordinates of triangle X'Y'Z'.

Apply the rules of roatation.

After a rotation of 270 degrees counterclockwise, the coordinates (x, y) becomes (y, -x).

Applying the rotation rule, we have the coordinates of X'Y'Z' below:

(x, y) ==> (y, -x)

X(-5, -4) ==> (-4, - -5), ==> X'(-4, 5)

Y(2, -2) ==> (-2, -2) ==> Y'(-2, -2)

Z(-3, -6) ==> (-6, - -3) ==> Z'(-6, 3)

Therefore, the coordinates of traingle X'Y'Z' are:

X'(-4, 5)

Y'(-2, -2)

Z'(-6, 3)

• Part B.

To select the general rule that describes the rotation mapping, apply the rotation rules for 270 degrees counterclockwise rotation.

We have:

(x, y) ==> (y, -x)

Therefore, the general rule that describes the rotation mapping is:

(x, y) ==> (y, -x)

ANSWER:

(a) X'(-4, 5)

Y'(-2, -2)

Z'(-6, 3)

(b) (x, y) ==> (y, -x)

User Majid Rajabi
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3.0k points