Answer:
The average distance each data value in the set is from the mean is:
2.8
Explanation:
We are asked to find the Mean absolute deviation i.e. MAD of the data set.
The data set is:
2010,2002,2005,2007,2001
Mean of the data is:

Now, the absolute difference is:

Now, the mean of these absolute deviation i.e. MAD is:

Hence, the answer is:
2.8