Question

Given a solution with a pOH of 13.6, what is the [OH-] of the solution?

13.6 M

2.51 x 10-14 M

0.4 M

3.98 x 10-1 M

Answer 1

10^-13.6 = 2.51x10^-14

Answer 2

2.51 x 10-14 M

Step-by-step explanation:

The definition of pOH is:

pOH = -log[OH-]

then, clearing of the equation [OH-] we have:

-pOH = log[OH-]

By properties of logarithms:

`[OH-] = 10^(-pOH)`

Replacing the values:

`[OH-] = 10^(-13.6)`

And if you use a calculator, you will see that
`10^(-13.6)=2.51x10^(-14)`