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What is the equation of the line that passes through (5, -2) and (-3, 4)? 3x - 4y - 7 = 0 3x + 4y - 7 = 0 -3x + 4y - 7 = 0

What is the equation of the line that passes through (5, -2) and (-3, 4)? 3x - 4y - 7 = 0 3x + 4y - 7 = 0 -3x + 4y - 7 = 0
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What is the equation of the line that passes through (5, -2) and (-3, 4)?

3x - 4y - 7 = 0
3x + 4y - 7 = 0
-3x + 4y - 7 = 0

User Ckknight
by
8.3k points

2 Answers

3 votes
The answer is B hope this helps
User Maoritzio
by
7.8k points
3 votes
The answer is 3x+4y-7=0. The line will have a negative slope. 
User Sufyan Siddique
by
7.8k points
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