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3 votes
Find the indicated sum for the geometric series:

∑4k=13k−1

User Dcbenji
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1 Answer

2 votes
if its this

\sum^(4)_(k=13) k-1

well start with the first term
13-1
add the 2nd term
14-1
add the 3rd term
15-1
andd the 4th term
16-1

since the summation only goes to 4, we stop here

13+14+15+16-4*1
would be the answer to your summation
User TechExplorer
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