Question

Two vertices of a right triangle have the coordinates (−2, 5) and (9, 5) .

What is the length of the side formed by these vertices?

Answer 1

I=√(y2-y1)^2+(x2-x1)^2 then substitute I
I=√(5-5)^2+(9+2)^2
I= √0^2+11^2
I=√121
I=11 your answer will be 11 units

Answer 2

Here, l = √(y2-y1)² + (x2-x1)²

Now, substitute the known values,
l = √(5 - 5)² + (9 + 2)²
l = √0² + 11²
l =√121
l = 11

In short, Your Answer would be 11 units

Hope this helps!