One number is 16 more than a second number. The sum of the first number and twice the second number is 139. What is the answer ?

Question

asked May 4, 2018 51.3k views

1 Answer

← Prev Question Next Question →

Ask a Question

Beeselmane · Answer 1 · 2018-05-11T11:49:24+0000

Answer first number = 57 second number = 41
x= 16 + y
x + 2y = 139

16+ y + 2y =139
16 + 3y =139
16-16 +3y = 139-16
3y = 123
3/3y = 123/3
y= 41

x= 16+y
x = 16+41
x= 57

One number is 16 more than a second number. The sum of the first number and twice the second number is 139. What is the answer ?

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

No related questions found

Categories

Other Questions