Question

if you dropped a ball while standing on the surface of mars at what rate would it accelerate toward the ground

Answer 1

3.71 m/s^2

Step-by-step explanation:

The acceleration of gravity on the surface of a planet can be found by using the following formula:

`g=(GM)/(r^2)`

where

`G=6.67 \cdot 10^(-11) m^3 kg^(-1) s^(-2)` is the gravitational constant

`M=6.39\cdot 10^(23) kg` is the mass of the planet (in this case, Mars)

`r=3.39\cdot 10^6 m` is the radius of the planet (in this case, Mars)

Substituting the numbers into the formula, we find

`g=((6.67\cdot 10^(-11))(6.39\cdot 10^(23) kg))/((3.39\cdot 10^6 m)^2)=3.71 m/s^2`