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The slope of the tangent line to a curve at any point (x, y) on the curve is x/y. What is the equation of the curve if (3, 1) is a point on the curve? x^2 + y^2 = 8 x + y = 8 x^2 − y^2 = 8 xy = 8
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The slope of the tangent line to a curve at any point (x, y) on the curve is x/y. What is the equation of the curve if (3, 1) is a point on the curve?

x^2 + y^2 = 8
x + y = 8
x^2 − y^2 = 8
xy = 8

User Musaffa
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1 Answer

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x^2-x^2=8 is your answer
User Richard Mosselveld
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