Question

In ΔDEF shown below, segment DG is an altitude:

Triangle DEF with segment DG drawn from vertex D and intersecting side EF.

Which of the following is a step towards proving the similarity of triangles ΔDEF and ΔGED? (6 points)


Segment EF is a hypotenuse.

Angle E is congruent to itself.

Segment ED is shorter than segment EF.

Segment EF is intersected by segment DG.

Answer 1

option 2 Angle E is congruent to itself.

Explanation:

Answer 2

I found the corresponding image.

The step towards proving the similarity of triangles DEF and GED is:

ANGLE E IS CONGRUENT TO ITSELF.

ΔDEF is a right triangle. Its hypotenuse is EF, its long leg is DF, its short leg is DE.
ΔGED is also a right triangle. Its hypotenuse is DE, its long leg is DG, its short leg is GE.

Only Angle E is in both triangles and its measure remains the same.