Question

Write an equation in slope-intercept form for the line described below:

Answer 1

y=-2x+8

Step-by-step explanation:

Given the line:

`y=(1)/(2)x-1`

We want to find a line that is perpendicular to the line with an x-intercept of 4.

Note: Two lines are perpendicular if the product of their slopes is -1.

Comparing y=½x-1 to the slope-intercept form y=mx+b, its slope =1/2.

Therefore, the slope of the line perpendicular to it = -2.

Since the x-intercept is 4, we have the point (4,0) on the line.

Using the point slope form:

`\begin{gathered} y-y_1=m(x-x_1) \\ y-0=-2(x-4) \\ y=-2x+8 \end{gathered}`

Therefore, the required line is: y=-2x+8