Question

One of the x-intercepts of the parabola represented by the equation y = 3x2 + 6x − 10 is approximately (1.08, 0). The other x-intercept of the parabola is approximately . (Round your answer to the nearest hundredth.)

Answer 1

Other x intercept is (-3.08,0)

Explanation:

One of the x-intercepts of the parabola represented by the equation y = 3x2 + 6x − 10

`y=3x^2+6x-10`

To find out x intercepts, we replace y with 0 and solve for x

`0=3x^2+6x-10`

To solve for x we apply quadratic formula

`x=(-b+-√(b^2-4ac))/(2a)`

`0=3x^2+6x-10`, a=3, b=6,c=-10

Plug in all the values in the formula

`x=(-b+-√(b^2-4ac))/(2a)`

`x=(-6+-√(6^2-4(3)(-10)))/(2(3))`

`x=(-6+-√(156))/(6)`

`x=(-6+-2√(39))/(6)`

Divide top and bottom by 3

`x=(-3+-√(39))/(3)`

x=1.08167 and x=-3.08167

Round your answer to nearest hundredth

x=1.08 and x=-3.08

Other x intercept is (-3.08,0)