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How many moles of glucose (C6H12O6) are in 1.6 liters of a 0.75 M C6H12O6 solution? show all work

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moles glucose =1.6 L× 0.75 mol/Let =1.2
User Chima
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Step-by-step explanation:

Molarity is defined as the number of moles in liter of solution.

Mathematically, Molarity =
(no. of moles)/(Volume in liter)

The data is given as volume is 1.6 liters and molarity is 0.75 M. Therefore, calculate the number of moles as follows.

Molarity =
(no. of moles)/(Volume in liter)

or, No. of moles =
Molarity * Volume in liter

= 0.75 M × 1.6 liter

= 1.2 moles

Thus, we can conclude that there are 1.2 moles of glucose in 1.6 liters of a 0.75 M C6H12O6 solution.

User Prahlad Yeri
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