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The median weight of the players is _____. 154 158 163 167 169

User Ckarbass
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by adding both together that'll be 811 but divided by 5,,, that be 162,2,,,therefore I think or am I be wrong the answer can be 163.....
User Tony Gibbs
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Answer: The median weight of the players is 163 (units).

Step-by-step explanation:

In an ordered data set ,

If number of data value (n)= odd

Then,
\text{Median}=\text{Middle-most value OR }(n+1)/(2)^(th)\text{ term}

If number of data value (n)= even

Then,
\text{Median}=((n)/(2)+1)^(th)\text{ term}

The given data of weight of the players :

154 158 163 167 169

To find median, first we check the given weights are in order.

Since all all the values are in an ascending order ( from lower to higher value )

, so we can move to the next step.

The number of observations = 5 , which is an odd number .

Therefore , Median= Middlemost value = 163

Hence, The median weight of the players is 163 (units).

User Meirav
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