Question

Solving systems by elemination x+y=3 x-y=1

Answer 1

`\left \{ {{x+y=3\:(I)} \atop {x-y=1\:(II)}} \right.`

by elemination


`\left \{ {{x+\diagup\!\!\!\!y=3} \atop {x-\diagup\!\!\!\!y=1}} \right.`

`\left \{ {{x=3} \atop {x=1}} \right.`
-------------

`2x = 4`

`x = (4)/(2)`

`\boxed{x = 2}`


Replace the found value of "x", to find the value of "y"

`x+y=3\:(I)`

`2 + y = 3`

`y = 3 - 2`

`\boxed{y = 1}`

Answer:
X = 2
Y = 1