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Solving systems by elemination x+y=3 x-y=1

1 Answer

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\left \{ {{x+y=3\:(I)} \atop {x-y=1\:(II)}} \right.

by elemination


\left \{ {{x+\diagup\!\!\!\!y=3} \atop {x-\diagup\!\!\!\!y=1}} \right.

\left \{ {{x=3} \atop {x=1}} \right.
-------------

2x = 4

x = (4)/(2)

\boxed{x = 2}


Replace the found value of "x", to find the value of "y"

x+y=3\:(I)

2 + y = 3

y = 3 - 2

\boxed{y = 1}

Answer:
X = 2
Y = 1
User Jarek Tkaczyk
by
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