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Write the expression (4x-2)×6(2x+7) in the standard form of a quadratic expression ax^{2}+bx+c. What are the values of the coefficients of each term and the constant term.

find the answer for a, b, and c

1 Answer

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(4x-2)×6(2x+7) =

(4x-2) × 12x + 42 =

48x^2 -24x + 168x -84 = 0

48x^2 +144x -84 = 0

a = 48 b = 144 and c = -84
and the solution is
x1=.5 and x2=-3.5

User Lasse Meyer
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