87,115 views
41 votes
41 votes
How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 20% antifreeze to get a mixture that is 50% antifreeze?

User Henrywright
by
2.8k points

1 Answer

23 votes
23 votes

Given

gallons which have 20% antifreeze solution = 80

Final concentration = 50% antifreeze solution

Find

Number of galloons with 60% antifreeze solution

Step-by-step explanation

Let the number of gallons with 60% antifreeze solution = x

According to question

0.6x+0.2(80) = 0.50(x+80)

0.6x+16=0.5x+40

0.1x=24

x=240

Final Answer

Hence 240 gallons of 60% antifreeze solution will be required

User Geremia
by
3.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.