Question

If _______ , what is f^-1(x)?

f–1(x) = 9x + 18
________
f–1(x) = 9x + 2
________

Answer 1

If f(x)=1/9x-2
then f^-1(x) will be
lets assume f(x)=y
y=1/9x-2
y+2=1/9x
9(y+2)=x
f^-1(x)=9(y+2)

rest u can do with the same method

Answer 2

we have

`f(x)=(1)/(9)x-2`

Let

`y=f(x)`

`y=(1)/(9)x-2`

To find the inverse

Exchanges the variables x for y and y for x

`x=(1)/(9)y-2`

Isolate the variable y

Multiply by
`9` both sides

`9x=y-18`

Adds
`18` both sides

`9x+18=y-18+18`

`y=9x+18`

Let

`f^(-1)(x)=y`

`f^(-1)(x)=9x+18` -------> the inverse function

therefore

the answer is

`f^(-1)(x)=9x+18`