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What is the distance between points (9, 4) and (–3, 4) on a coordinate plane? units
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What is the distance between points (9, 4) and (–3, 4) on a coordinate plane? units

User Metalheart
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8.4k points

1 Answer

4 votes
d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(9,4)....x1 = 9 and y1 = 4
(-3,4)...x2 = -3 and y2 = 4
now we sub
d = sqrt (-3 - 9)^2 + (4 - 4)^2
d = sqrt (-12^2 + 0^2)
d = sqrt -12^2
d = sqrt 144
d = 12 units
User Davi Lima
by
9.1k points
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