Question

A sample of neon occupies a volume of 752 ml at 25 0

c. what volume will the gas occupy at 50.0 c?

Answer 1

`V_(initial) = 752\:mL`

`T_(initial) = 25.0^0C`
converting to Kelvin
TK = TC + 273
TK = 25.0 + 273 → TK = 298.0 →
`T_(initial) = 298.0\:K`

`V_(final) = ? (in\:milliliters)`

`T_(final) = 50.0^0C`
TK = TC + 273
TK = 50.0 + 273 → TK = 323.0 →
`T_(final) = 323.0\:K`

By the first Law of Charles and Gay-Lussac, we have:

`( V_(i) )/( T_(i) ) = ( V_(f) )/( T_(f) )`

Solving:

`( V_(i) )/( T_(i) ) = ( V_(f) )/( T_(f) )`

`( 752 )/( 298.0 ) = ( V_(f) )/( 323.0 )`
Product of extremes equals product of means:

`298.0* V_(f) = 752*323.0`

`298.0 V_(f) = 242896`

`V_(f) = (242896)/(298.0)`

`\boxed{\boxed{V_(f) \approx 815.08\:mL}}\end{array}}\qquad\quad\checkmark`