Question

James Bond is rappelling down a cliff face to infiltrate an enemy base, but there is a gust of wind, and he starts swinging side to side. If he makes a 45 m pendulum once you factor in the length of the rope, how long does it take for him to complete a full oscillation? He'll need to know this so that he can time his distraction of the guards

Answer 1

To calculate James Bond's full oscillation time, use the period formula for a simple pendulum. With a 45 m rope, it takes approximately 13.46 seconds for one complete swing.

Step-by-step explanation:

To calculate the time for one full oscillation of James Bond swinging side to side on a pendulum, we use the formula for the period T of a simple pendulum:

T = 2π√(L/g),

where L is the length of the rope (45 m) and g is the acceleration due to gravity (approximately 9.81 m/s2). Plugging the values into the formula gives us:

T = 2π√(45 m / 9.81 m/s²)

= 2π√(4.592s²)

= 2π × 2.143

= 13.46 s

By calculating this we find that T is approximately 13.46 seconds for a full oscillation. Note that this is under the assumption that the amplitude is small and air resistance is negligible, which are typical assumptions made when analyzing pendulum motion in simple physics problems.

Answer 2

13.46 s

Step-by-step explanation:

The time it takes James Bond to complete one full oscillation is the period of a pendulum of length, l which is, T = 2π√(l/g) where l = length of pendulum = length of rope = 45 m and g = acceleration due to gravity = 9.8m/s²

So, substituting the values of the variables into the equation, we have

T = 2π√(l/g)

= 2π√(45 m/9.8m/s²)

= 2π√(4.592s²)

= 2π × 2.143

= 13.46 s

So, it takes 13.46 s for him to complete one full oscillation.