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28 votes
28 votes
When doing a chin-up, a student lifts her body with a force of 400N and a distance of 0.25 meters in 2 seconds. What is the power delivered by the students biceps?

User Zapatilla
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1 Answer

25 votes
25 votes

Given:

The student lifts her body with a force F = 400 N

The distance is d = 0.25 N

The time is t = 2 s

To find: The power delivered by student's biceps.

Step-by-step explanation:

The formula to calculate power is


P=(F* d)/(t)

Substituting the values, the power will be


\begin{gathered} P=(400*0.25)/(2) \\ =\text{ 50 W} \end{gathered}

Final Answer: The power delivered by student's biceps is 50 W.

User Mazunki
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3.1k points