Question

When doing a chin-up, a student lifts her body with a force of 400N and a distance of 0.25 meters in 2 seconds. What is the power delivered by the students biceps?

Answer 1

Given:

The student lifts her body with a force F = 400 N

The distance is d = 0.25 N

The time is t = 2 s

To find: The power delivered by student's biceps.

Step-by-step explanation:

The formula to calculate power is

`P=(F* d)/(t)`

Substituting the values, the power will be

`\begin{gathered} P=(400*0.25)/(2) \\ =\text{ 50 W} \end{gathered}`

Final Answer: The power delivered by student's biceps is 50 W.