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Calculate the number of gams of nitrogen dioxide that are produced from 4 moles of nitric oxide

2NO(g) + O2(g) → 2NO2(g)


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Answer: 184 g of nitrogen dioxide that are produced from 4 moles of nitric oxide

Step-by-step explanation:

The balanced chemical reaction is:


2NO(g)+O_2(g)\rightarrow 2NO_2(g)

According to stoichiometry :

2 moles of
NO produce = 2 moles of
NO_2

Thus 4 moles of
NO will require=
(2)/(2)* 4=4moles of
NO_2

Mass of
NO_2=moles* {\text {Molar mass}}=4moles* 46g/mol=184g

Thus 184 g of nitrogen dioxide that are produced from 4 moles of nitric oxide

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