Question

A grinding wheel 0.35 m in diameter rotates at 2500 rpm. What is the linear speed of apoint on the edge of the grinding wheel?

Answer 1

Linear velocity (V) = r* w

where:

r = radius = diameter/2= 0.35 /2 = 0.175 m

w= angular velocity = rpm = 2500 = 2500/60 = 125/3 rps

1 revolution = 360° = 2pi rad/s = 125/3 2pi rad/s

= 261.8 rad/s

v = 0.175 m * 261.8 m/s = 45.8 m/s