Question

A sample of gas under a pressure of 622 kPa has a volume of 233 mL. The pressure is increased to 988 kPa, while the temperature remains constant. What volume will the gas occupy at this pressure?

Answer 1

Data:
V1 (initial volume) = 233 mL
P1 (initial pressure) = 622 kPa
V2 (final volume) = ? (mL)
P2 (final pressure) = 988 kPa

Formula:
P1 * V1 = P2 * V2

Solving:
P1 * V1 = P2 * V2
622 * 233 = 988 * V2
114926 = 988 V2
988 V2 = 114926

`V_(2) = (114926)/(988)`

`\boxed{\boxed{V_(2) \approx 146.68\:mL}}\end{array}}\qquad\quad\checkmark`