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Solve the equation Also look for extraneous solutions Please show your work and explain the steps
asked
Mar 5, 2018
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4
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Solve the equation
Also look for extraneous solutions
Please show your work and explain the steps
Mathematics
high-school
Nabin Kunwar
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Nabin Kunwar
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-3 = -x + √(-2x + 6)
Squaring both sides,
9 = -x² - 2x + 6
x² + 2x + 3 = 0
x² -x + 3x + 3 = 0
-x(x + 1) 3(x + 1)
(3 - x) (x + 1) = 0
x = 3 or -1
Hope this helps!
Shhdharmen
answered
Mar 7, 2018
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Shhdharmen
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2
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−3=−x+
√
−2(x−3)
−3=−x+
√
2(x−3)
ı
−3+x=ı
√
2(x−3)
(x−3)
2
=−2(x−3)
6
x
2
−6x+9=−2x+6
x
2
−6x+9+2x−6=0
x
2
−4x+9−6=0
x
2
−4x+3=0
(x−3)(x−1)=0
x=3,1
x=3
Tony Bao
answered
Mar 8, 2018
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Tony Bao
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