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Prove tan5utan3u=(tan^24utan^2u)/(1-tan^24utan^2u)

User Angelita
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1 Answer

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\tan5u\tan3u=(\tan^24u\tan^2u)/(1-\tan^24u\tan^2u)

This is not true (assuming I've understood the question correctly).

Consider
u=\frac\pi4. Then


\tan\frac{5\pi}4\tan\frac{3\pi}4=1(-1)=-1

while


(\tan^2\pi\tan^2\frac\pi4)/(1-\tan^2\pi\tan^2\frac\pi4)=(0(1))/(1-0(1))=0
User Dvd
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