Question

What is the boiling point of a 0.75-molal solution of a non-volatile non-electrolyte solute in water? Kb for water = 0.52 degrees C/ molal.

99.61 °C
100.0 °C
100.39 °C
101.44 °C

Answer 1

The answer is C. I just did this assignment

Answer 2

take the molality and multiply it by the Kb
0.75 × 0.52 = 0.39 C

then add the boiling pt to the 0.39
100 + 0.39 = 100.39 C