Question

The sum of three consecutive natural numbers is 1410, find the numbers.The three numbers in increasing order are  ,  , and  ,

Answer 1

number 1 = x

number 2 = x + 1

number 3 = x + 2

then

`\begin{gathered} x+x+1+x+2=1410 \\ 3x+3=1410 \\ 3x+3-3=1410-3 \\ 3x=1407 \\ (3x)/(3)=(1407)/(3) \\ x=469 \end{gathered}`

therefore:

number 1 = 469

number 2 = 470

number 3 = 471