Question

Round all sides to the nearest foot and all angles to the nearest tenth of a degree look at photo for accurate descriptions

Answer 1

Okay, here we have this:

Considering the provided information, we are going to solve the triangle, so we obtain the following:

`\begin{gathered} b=\sqrt[]{a^2+c^2-2ac\cdot\cos\mleft(B\mright)} \\ b=\sqrt[]{631^2+199^2-2(631)(199)\cdot\cos (104.8)} \\ b\approx708ft \end{gathered}`
`\begin{gathered} \angle A=arccos((b^2+c^2-a^2)/(2bc)) \\ \angle A=arccos((708.46^2+199^2-631^2)/(2(708.46)(199))) \\ \angle A\approx59.4degrees \end{gathered}`
`\begin{gathered} \angle C=arccos((b^2+a^2-c^2)/(2ba)) \\ \angle C=arccos((708.46^2+631^2-199^2)/(2(708.46)(631))) \\ \angle C\approx15.8degrees \end{gathered}`