Question

PLEASE HELP!!!! ASAPP

Determine the number of moles of air present in 1.35 L at 750 torr and 17.0°C. What is the number of moles present?

Answer 1

.056

Step-by-step explanation:

750*1.35/

62.396*290=.05595778

n=.056

Answer 2

Answer : The number of moles of air present is, 0.055 mole

Solution :

Using ideal gas equation :

`PV=nRT`

where,

P = pressure of the gas = 750 torr = 0.98 atm (1 atm = 760 torr)

V = volume of the gas = 1.35 L

T = temperature of the gas =
`17^oC=17+273=290K`

R = gas constant = 0.0821 Latm/moleK

n = number of moles of air = ?

Now put all the given values in this formula, we get the number of moles of air present.

`(0.98atm)* (1.35L)=n* (0.0821Latm/moleK)* (290K)`

`n=0.055mole`

Therefore, the number of moles of air present is, 0.055 mole