Question

A force of 150 newtons was necessary to lift a tree. A total of 250 joules of work was done. How far was the tree lifted?

Answer 1

Given,

The force applied to lift the tree, F=150 N

The work done in lifting the tree, W=250 J

The work done in lifting the tree is the product of the force applied and the height through which the tree was lifted.

Thus,

`\begin{gathered} W=F* d \\ \Rightarrow d=(W)/(F) \end{gathered}`

Where d is the height through which the tree was lifted.

On substituting the known values,

`\begin{gathered} d=(250)/(150) \\ =1.67\text{ m} \end{gathered}`

Thus the tree was lifted through a height of 1.67 m